6 x -2.

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2. 5(x + 6) = x + 38, given. 3. 5x + 30 = x + 38, distribute the 5 to the terms inside the parentheses: 4. Next, we'll gather the x terms on one side of the equation and the constant terms on the other side. Let's subtract x from both sides: 5x - x + 30 = x - x + 38. Combining like terms: 4x + 30 = 38. 5. Now, we'll isolate the term with x by ...

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Suppose we have a quadratic function in the following format: If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is . To find the vertex, the function has to be in standard form. Thus: Which has coefficients . The vertex of the quadratic function is (2,-16).6x2-6x=0 Two solutions were found : x = 1 x = 0 Step by step solution : Step 1 :Equation at the end of step 1 : (2•3x2) - 6x = 0 Step 2 : Step 3 :Pulling out like terms : 3.1 ... 6x2-36x=0 Two solutions were found : x = 6 x = 0 Step by step solution : Step 1 :Equation at the end of step 1 : (2•3x2) - 36x = 0 Step 2 : Step 3 :Pulling out ...

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Singkatnya, kamu mengalikannya secara diagonal. Jadi, kalikan penyebut pertama, 6, dengan pembilang kedua, 2, sehingga kamu mendapatkan 12 di sisi kanan persamaan. …

can't be factored Explanation: D = b^2 - 4ac = 36 - 108 < 0. Since D is not a perfect square, this trinomial can't be factored. x2-5x+1 Final result : x2 - 5x + 1 Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-5x+1 The first term is, x2 its coefficient is 1 .

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